Two years ago, a father was 5 times as old as his son. Two years later (from now), his age will be 8 more than 3 times the son’s age. Find the father’s present age.

Question

Two years ago, a father was 5 times as old as his son. Two years later (from now), his age will be 8 more than 3 times the son&#8217;s age. Find the father&#8217;s present age.

Accepted Answer

42 years. Let father = f, son = s .  (f-2) = 5(s-2) => f = 5s - 8 .  (f+2) = 3(s+2) + 8 => f = 3s + 12 .  Equating: 5s - 8 = 3s + 12 .  s = 10, f = 42 years

Two years ago, a father was 5 times as old as his son. Two years later (from now), his age will be 8 more than 3 times the son’s age. Find the father’s present age.

Explanation