The ages of two persons differ by 16 years. If 6 years ago, the elder one was 3 times as old as the younger one, find the elder’s present age.

Question

The ages of two persons differ by 16 years. If 6 years ago, the elder one was 3 times as old as the younger one, find the elder&#8217;s present age.

Accepted Answer

30 years. Let younger = y, elder = y + 16 .  (y + 16 - 6) = 3(y - 6) .  y + 10 = 3y - 18 .  2y = 28 => y = 14 .  Elder's age = 14 + 16 = 30 years