A man’s age is 4 times that of his son. Five years ago, the man’s age was 7 times the son’s age. Find the son’s present age.

Question

A man&#8217;s age is 4 times that of his son. Five years ago, the man&#8217;s age was 7 times the son&#8217;s age. Find the son&#8217;s present age.

Accepted Answer

10 years. Let son = s, man = 4s .  (4s - 5) = 7(s - 5) .  4s - 5 = 7s - 35 .  3s = 30 => s = 10 years